If the family $\mathtt{gen}$ satisfies the deletion condition, any word mapping to $1$ under $\mathtt{gen}$ has even length. (One can repeatedly delete pairs of letters by the deletion condition.)
If a word of length $2m$ with $m > 1$ maps to $1$, then its initial segment of length $m + 1$ admits a strictly shorter word with the same product: namely, the reverse of the second half.
Transport of the braid relation: if $(\mathtt{gen}\,s \cdot \mathtt{gen}\,t)^m = 1$ in $W$, then the same braid relation $(\mathtt{simple}\,s \cdot \mathtt{simple}\,t)^m = 1$ holds in the abstract Coxeter group associated to $\mathtt{gen}$.
Peeling off the first factor: $\mathtt{consecProd}\,g\,k\,(m+1) = g(k) \cdot \mathtt{consecProd}\,g\,(k+1)\,m$.
Peeling off two factors: $\mathtt{consecProd}\,g\,k\,(m+2) = g(k)\,g(k+1) \cdot \mathtt{consecProd}\,g\,(k+2)\,m$.
If for every $k$ the $m$-fold product starting at $k$ equals the same product but with the first factor replaced by $g(k+2)$, then $g$ is two-step periodic: $g(k) = g(k+2)$ for all $k$.
Cyclic extension of $\mathtt{gen}\circ\mathtt{word}$ to all of $\mathbb{N}$: at index $k$ it returns the generator at position $k \bmod n$.
Instances For
For a word of length $2m$ ($m \ge 2$), if the cyclic generator satisfies the $L$-type identity, then the word is two-step periodic at the level of generator values: $\mathtt{gen}(\mathtt{word}[k]) = \mathtt{gen}(\mathtt{word}[k+2])$ whenever both indices fit.