A polynomial P : ℝ[x₁, …, x_d] bisects a measurable set U ⊆ ℝ^d if the
parts of U where P > 0 and where P < 0 have equal Lebesgue volume.
Instances For
The signed volume vol{P > 0 in U} − vol{P < 0 in U} as a real number; this
function is zero exactly when P bisects U (assuming U is bounded).
Instances For
For a bounded set U, vanishing of the signed volume signedVol d P U implies
that P bisects U.
A nontrivial linear combination of linearly independent polynomials is nonzero.
Any real-linear combination of polynomials of total degree at most D itself
has total degree at most D.
A point on the unit sphere S^n ⊆ ℝ^{n+1} has, in particular, a nonzero
coordinate vector.
The space of polynomials in d variables of total degree at most D has
dimension binom(D + d, d); in particular it admits a linearly independent
family of that size all of whose elements have total degree ≤ D.
Continuity of the signed-volume map. For a fixed basis of polynomials of bounded
degree and bounded open sets U_i, the map sending a coefficient vector x on
the sphere to the tuple of signed volumes (signedVol d (∑ x_j basis_j) U_i)_i is
continuous as a map S^n → ℝ^n.
Polynomial Ham Sandwich Theorem. Given n bounded open sets U_1, …, U_n
in ℝ^d and a degree bound D with n ≤ binom(D + d, d) − 1, there exists a
nonzero polynomial P of total degree ≤ D whose zero set bisects every U_i.
This is the polynomial generalization of the classical Ham Sandwich theorem,
proved via Borsuk–Ulam applied to signed volumes.