The $(n-1)$-dimensional Hausdorff measure on the unit sphere $S^{n-1}$, serving as the
unnormalized surface-area measure used to define normalizedSphereMeasure.
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The total $(n-1)$-Hausdorff surface measure of the sphere $S^{n-1}$ is finite.
The uniform probability measure on $S^{n-1}$, defined by normalizing the $(n-1)$-Hausdorff surface measure: $\mu(A) = \operatorname{vol}(A) / \operatorname{vol}(S^{n-1})$.
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The normalized sphere measure is monotone with respect to set inclusion.
Subadditivity (union bound) of the normalized sphere measure: $\mu(A \cup B) \le \mu(A) + \mu(B)$.
The normalized measure of the spherical cap $\{x \in S^{n-1} \mid x_1 \ge \varepsilon\}$, i.e. $\mathbb{P}_{x \sim S^{n-1}}(x_1 \ge \varepsilon)$ (with the convention that the value is $0$ when $n = 0$).
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For $\varepsilon > 1$ the cap $\{x \in S^{n-1} \mid x_1 \ge \varepsilon\}$ is empty, hence has measure $0$.
Spherical cap concentration (Theorem 9.4.11). For a uniformly random unit vector $x \sim S^{n-1}$ and $\varepsilon \ge 0$, $\mathbb{P}(x_1 \ge \varepsilon) \le \exp(-n \varepsilon^{2}/2)$.
Contrapositive helper: if the normalized measure of some set $A$ is positive, then the total surface volume of $S^{n-1}$ is nonzero (i.e. the sphere is genuinely $(n-1)$-dimensional).
Probability complement: $\mu(A^c) = 1 - \mu(A)$ for the normalized sphere measure, provided the total surface volume is nonzero.
A set of positive normalized sphere measure is nonempty.
Key intermediate step in the concentration of measure on $S^{n-1}$: if $\mu(A) \ge 1/2$, then $1 - \mu(A_t) \le \mathbb{P}\!\big(x_1 \ge t/\sqrt{2}\big)$ for every $t \ge 0$, obtained from Lévy's isoperimetric inequality.
Concentration of measure on the sphere (Corollary 9.4.12). If $\mu(A) \ge 1/2$ then $\mu(A_t) \ge 1 - \exp(-n t^{2}/4)$ for every $t \ge 0$.
Existence of a median for any function $f : S^{n-1} \to \mathbb{R}$: there is some $m \in \mathbb{R}$ such that both $\{f \le m\}$ and $\{f \ge m\}$ have normalized sphere measure at least $1/2$.
For a $1$-Lipschitz function $f : S^{n-1} \to \mathbb{R}$ with median bound $\mu(f \le m) \ge 1/2$, the upper tail $\{f > m + t\}$ has measure at most $1 - \mu(\text{thickening}_t \{f \le m\})$. This is the geometric link between Lipschitz tails and isoperimetric thickening.
One-sided concentration for $1$-Lipschitz functions on the sphere: if $m$ is a median of $f$ then $\mu(f > m + t) \le \exp(-n t^{2}/4)$ for all $t \ge 0$.
Concentration of $1$-Lipschitz functions on the sphere (Corollary 9.4.14). For any $1$-Lipschitz $f : S^{n-1} \to \mathbb{R}$ there exists a median $m \in \mathbb{R}$ such that $\mu(|f - m| > t) \le 2 \exp(-n t^{2}/4)$ for every $t \ge 0$.