The threshold $t = \lceil 10 \sqrt{n} \rceil$ used in Theorem 5.3.2: we show that $G(n, 1/2)$ has no $K_t$-subdivision with high probability.
Instances For
The union bound on the probability that $G(n, 1/2)$ contains a $K_t$-subdivision, for $t = \lceil 10\sqrt n \rceil$: $\binom{n}{t} \cdot e^{-t^2/10}$.
Instances For
Lower bound on hajosParam: $10\sqrt n \leq \lceil 10\sqrt n \rceil$.
Upper bound on hajosParam: $\lceil 10\sqrt n \rceil \leq 10\sqrt n + 1$.
Squaring the lower bound on hajosParam: $100 n \leq t^2$.
The union bound subdivisionUnionBound is nonnegative.
Asymptotic comparison: for all sufficiently large $n$, $t \log n \leq 2n$ where $t = \lceil 10\sqrt n \rceil$.
The sequence $e^{-n}$ tends to $0$ as $n \to \infty$.
For all sufficiently large $n$, $\binom{n}{t} e^{-t^2/10} \leq e^{-n}$ with $t = \lceil 10\sqrt n \rceil$.
The union bound subdivisionUnionBound n tends to $0$ as $n \to \infty$.
Counterexample to Hajós's conjecture (Theorem 5.3.2). If $\text{probKtSubdiv}(n)$ is the probability that $G(n, 1/2)$ contains a $K_t$-subdivision with $t = \lceil 10\sqrt n \rceil$, and is dominated by the union bound, then it tends to $0$, giving a $K_t$-subdivision-free graph of chromatic number $\Omega(n / \log n)$ asymptotically larger than $t$.