A vector that is both positive and negative everywhere is zero.
The bilinear form vanishes when its left argument is zero.
Convenience wrapper: dropping a prefix of a reduced word leaves a reduced word.
The simple root $e_s$ is not negative (its $s$-coordinate is $1 > 0$).
If $w \cdot e_s$ is negative for a reduced word $w$, then $s$ is a right descent: $\ell(ws) < \ell(w)$.
Faithfulness of the geometric (Tits) representation: the homomorphism $W \to \operatorname{GL}(\mathbb{R}^B)$ given by simple reflections is injective.
If $v$ is positive, $\sigma_t v$ is negative, and $\langle v, v\rangle = 1$, then $v = e_t$. This is the geometric "unique root" step that powers the sign-change exchange.
If $w \cdot e_s = e_t$ geometrically, then $s_t \cdot w = w \cdot s_s$ in the Coxeter group.
Exchange at the leading position: if $\mathrm{tail} \cdot e_s = e_t$, deleting the head $t$ realizes the exchange $w_{\text{tail}} = (t :: \mathrm{tail}) \cdot s$.
Sign change exchange theorem (unconditional): if a reduced word $w$ satisfies $w \cdot e_s$ is negative, then there is an index $i$ such that $w' \cdot s = w$ where $w'$ is $w$ with its $i$-th letter removed. This is the geometric form of the exchange condition.