Axiomless form of standardParabolicInjective: distinct subsets $S_1, S_2 \subseteq S$
yield distinct standard parabolics $P_{S_1} \ne P_{S_2}$, derived directly from the
BN-pair axioms (via BruhatProperties.fromAxioms).
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Axiomless form of parabolicsAreSubgroups: each $P_{S'}$ contains $1$ and is closed
under multiplication and inverses, derived from the BN-pair axioms alone.
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Every Borel subgroup $B$ is contained in any standard parabolic $P_{S'}$: since $1 \in W_{S'}$, the cell $B \cdot 1 \cdot B = B$ sits inside $P_{S'} = BW_{S'}B$.
Classification of subgroups containing $B$. Every subgroup $P \leq G$ with $B \leq P$ equals some standard parabolic $P_{S'}$, where $S' = \{s \in S : BsB \subseteq P\}$. Derived directly from the BN-pair axioms.
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Standard parabolics are self-normalizing (axiomless form). If $g \in G$ normalizes $P_{S'}$ in the sense $gP_{S'}g^{-1} = P_{S'}$, then $g \in P_{S'}$. That is, $N_G(P_{S'}) = P_{S'}$.
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No two distinct standard parabolics are conjugate (axiomless form). If $gP_{S_1}g^{-1} = P_{S_2}$ for some $g \in G$, then $S_1 = S_2$. Equivalently, distinct subsets $S_1 \ne S_2$ of the simple roots give parabolics that are not even conjugate in $G$.
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Convenience alias: $B \subseteq P_{S'}$ for every $S' \subseteq S$.
Convenience alias for subgroupsOverB_eq_parabolic': every subgroup containing $B$
is a standard parabolic.
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Convenience alias: standard parabolics are self-normalizing, $N_G(P_{S'}) = P_{S'}$.
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Convenience alias: distinct standard parabolics are not $G$-conjugate.