If $v(a) < 0$, then $v(1+a) = v(a)$ by the ultrametric inequality applied to $\min(v(1), v(a)) = v(a)$.
If $v(a) > 0$, then $v(1+a) = 0$ by the ultrametric inequality applied to $\min(v(1), v(a)) = 0$.
If $v(a) < 0$ then $1 + a \neq 0$: otherwise $v(1+a) = \infty$, contradicting $v(1+a) = v(a) < 0$.
An additive valuation turns finite products into finite sums: $v\!\left(\prod_{i \in s} f(i)\right) = \sum_{i \in s} v(f(i))$.
Threshold ultrametric inequality for finite sums: if $N < v(f(i))$ for all $i \in s$, then $N < v\!\left(\sum_{i \in s} f(i)\right)$.
Weak Approximation for Function Fields (Corollary 20.5). Given finitely many pairwise incomparable surjective discrete additive valuations $v_1, \ldots, v_n$ on a field $F$, target elements $f_1, \ldots, f_n \in F$ and any threshold $N \in \mathbb{Z}$, there exists a single $g \in F$ with $v_i(g - f_i) > N$ for every $i$.