The affine scheme $\mathrm{Spec}\, R$ for a commutative ring $R$.
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The morphism of schemes $\mathrm{Spec}\, \overline{k} \to \mathrm{Spec}\, k$ induced by the algebraic closure inclusion $k \hookrightarrow \overline{k}$.
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Base change of a $k$-scheme $X$ along the algebraic closure, producing the $\overline{k}$-scheme $X_{\overline{k}} := X \times_{\mathrm{Spec}\, k} \mathrm{Spec}\, \overline{k}$.
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The base change $X_{\overline{k}}$ is canonically a scheme over $\mathrm{Spec}\, \overline{k}$.
Definition 26.1. Two $k$-schemes $X$ and $Y$ are twists of each other if they become isomorphic over the algebraic closure: $X_{\overline{k}} \cong Y_{\overline{k}}$ as $\overline{k}$-schemes.
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Reflexivity of the twist relation: every scheme is a twist of itself.
Transitivity of the twist relation: if $X$ is a twist of $Y$ and $Y$ is a twist of $Z$, then $X$ is a twist of $Z$.
A genus-one curve $C$ is a twist of an elliptic curve $E$ if its Jacobian becomes isomorphic to $E$ over the algebraic closure $\overline{k}$, via a Weierstrass variable change.
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Theorem 26.3 (existence of an elliptic curve with prescribed $j$-invariant). Every genus-one curve $C$ over $k$ is a twist of some elliptic curve $E$ over $k$ sharing the same $j$-invariant.
Two elliptic curves over $k$ are isomorphic over $k$ if there exists a Weierstrass variable change defined over $k$ taking one to the other.
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No rational number satisfies $q^4 = 4$; equivalently, $\sqrt[4]{4}$ is irrational. Used to exhibit nontrivial twists over $\mathbb{Q}$.
The elliptic curves $y^2 = x^3 - x$ and $y^2 = x^3 - 4x$ over $\mathbb{Q}$ are not isomorphic over $\mathbb{Q}$, even though they have the same $j$-invariant. Concrete witness that nontrivial twists exist over $\mathbb{Q}$.