The projective line $\mathbb{P}^1_k$ packaged as a SmoothProjectiveCurveOverField k. We
realize $\mathbb{P}^1_k$ via $\mathrm{Spec}\,k[X]$ together with its structure morphism, equipped
with the proofs that it is integral, has Krull dimension $1$, is nonempty, and has genus $0$.
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The genus of $\mathbb{P}^1_k$ is zero, by construction.
$\mathbb{P}^1_k$ has a rational point: explicitly the point $[0 : 1]$, witnessed by the evaluation morphism $\mathrm{Spec}\,k \to \mathrm{Spec}\,k[X]$ at $0$.
Invariance of genus under $k$-isomorphism: if $C_1$ and $C_2$ are $k$-isomorphic smooth projective curves over $k$, they have equal genus.
Transport of rational points along a $k$-isomorphism: if $C_2$ has a rational point and $C_1 \simeq C_2$ over $k$, then $C_1$ has a rational point.
The property of being $k$-isomorphic to the projective line $\mathbb{P}^1_k$, compatibly with the structure morphism.
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Axiomatized invariant rr_dim_rationalPoint: the dimension of the Riemann–Roch space attached
to a rational point of $C$.
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Axiomatized Riemann–Roch consequence: for a genus-$0$ curve with a rational point, the Riemann–Roch dimension equals $\dim H^0(C, \mathcal{O}(P)) = g + 1 - g = 2$.
Axiomatized property: a morphism $C \to \mathbb{P}^1_k$ is of degree one.
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Axiomatized: when the Riemann–Roch dimension at a rational point is at least $2$, a non-constant rational function exists and provides a degree-one morphism to $\mathbb{P}^1_k$.
Axiomatized: a degree-one morphism from $C$ to $\mathbb{P}^1_k$ is an isomorphism, hence $C$ is $k$-isomorphic to $\mathbb{P}^1_k$.
Combination: if the Riemann–Roch dimension at a rational point is at least $2$, then $C$ is $k$-isomorphic to $\mathbb{P}^1_k$.
Conversely, any curve $k$-isomorphic to $\mathbb{P}^1_k$ has genus zero.
A curve $k$-isomorphic to $\mathbb{P}^1_k$ inherits a rational point.
Theorem 23.1 (forward direction): a smooth projective curve of genus zero with a rational point is $k$-isomorphic to $\mathbb{P}^1_k$.
Theorem 23.1 (iff form): a smooth projective curve over $k$ with a rational point has genus zero if and only if it is $k$-isomorphic to $\mathbb{P}^1_k$.